Check my math...
So we can caluculate using Ohm's Law that a Gerbing jacket liner (6.4 amp draw at 12 volts) has a resistance of 1.875 ohms?
I = V/R or V/I = R therefore 12/6.4 = 1.875 ohms.
Maybe I should have bought the 26ga wire at .041 ohms/ft. instead of the 30ga at .1 ohms/ft. to get more even heating and cover a larger area?