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harderkev · 11-11-2006, 08:45 AM

So we can caluculate using Ohm's Law that a Gerbing jacket liner (6.4 amp draw at 12 volts) has a resistance of 1.875 ohms?

I = V/R or V/I = R therefore 12/6.4 = 1.875 ohms.

Maybe I should have bought the 26ga wire at .041 ohms/ft. instead of the 30ga at .1 ohms/ft. to get more even heating and cover a larger area?

Kev.

11-11-2006, 08:45 AM	#86
harderkev Slab Sucks! Joined: Jun 2005 Location: Santa Margarita, Ca. Oddometer: 356	Check my math... So we can caluculate using Ohm's Law that a Gerbing jacket liner (6.4 amp draw at 12 volts) has a resistance of 1.875 ohms? I = V/R or V/I = R therefore 12/6.4 = 1.875 ohms. Maybe I should have bought the 26ga wire at .041 ohms/ft. instead of the 30ga at .1 ohms/ft. to get more even heating and cover a larger area? Kev.